The velocity acquired by the body when it falls through a height h is v. If it further travel a distance x what is the change in its velocity
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A body is fall from a certain height, velocity at height h , is v.
here, initial velocity of body, u = 0
using formula, v² = u² + 2as
or, v² = 0 + 2gh = 2gh
or, v = √(2gh).....(1)
body further travels a distance x,
then, initial velocity for this situation, u = = √(2gh) , s = x
using formula, v² = u² + 2as
or, v'² = (√2gh)² + 2gx
or, v'² = 2gh + 2gx
or , v' = √{2g(h + x)}
now ,change in velocity = v' - v
= √{2g(h + x)} - √(2gh)
= √(2gh) [ √{(h + x)/h} - 1 ]
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