Question

The velocity associated with a proton moving in a potential difference of 1000 V is 4.37 x 10⁵ ms⁻¹. If the hockey ball of mass 0.1 kg is moving with this velocity, calculate the wavelength associated with this velocity.

Answer 1

λ = h/mv

= 6.626x10-34 / (0.1)(4.37x105)

= 1.515x10-28m

Answer 2

Λ = h/mv = 6.626x10-34/(0.1)(4.37x105) = 1.515x10-28m.

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