the velocity at the maximum height of a projectile is half of its initial velocity of projection. the angle of projection is
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As ucosθ0=u/2ucosθ0=u/2∴θo=60∘∴θo=60∘So R=u2sin(2×60∘)gR=u2sin(2×60∘)g=3–√2u2g
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At maximum height velocty = uCosθ
uCosθ = u/2
Cosθ = 1/2
θ = 60°
Angle of projection is 60°
uCosθ = u/2
Cosθ = 1/2
θ = 60°
Angle of projection is 60°
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