Question

The velocity at the maximum height of a projectile is half of its initial velocity of projection u. Its range on horizontal plane is?

Answer 1

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Answer 2

hi,

At maximum height

velocity = uCosθ

u/2 = uCosθ

θ = 60°

R = u² Sin(2θ) / g

= u² Sin(2 × 60°) / g

= u²√3 / (2g)

Range on horizontal plane is u²√3 / (2g)

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