Question

the velocity at the maximum height of a projectile is root 3/2 times its initial velocity of projection (u). its range on the horizontal plane is

Answer 1

vel at maximum height =ucos@
a/c ucos@/u=root3/2
cos@=root3/2
@=30
Range=u^2sin2@/g
=u^2sin60/g
=root3/2(u^2/g)

Answer 2

Answer:

answer is given in the attachment