Question

The velocity at the maximum height of projectile is half of its initial velocity u. It's rang on horizontal plane is

Answer 1

Velocity at maximum height is 0 in y direction but something say(ucosФ).
=>initial velocity is u
Acc. to ques. ucosФ=u/2
=>Ф=60°
Now, range=$u^{2}$sin2Ф/g
=>R=$\sqrt{3}$$u^{2}$/2g