Question

The velocity changes from 45 m/ S to 60 m/S in three seconds. what is its acceleration?​

Answer 1

Explanation:

$\blue{\mathbb{Here}} \\ \: \: \: u (initial \: velocity)= 45m/s \\ \: \: \: v(final \: velocity) = 60m/s \\ \: \: \: t(time) = 3 s \\ \\ \\ \\ So, \: \: \: \: \: a \: = \frac{v - u}{t} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{(60 - 45)m/s }{3 s} = \frac{15 m/s}{3s} \\ \boxed{\bold{\blue{acceleration = 5 m/ {s}^{2}}}}$