Question

the velocity displacement graph of a particle moving along a straight line is shown.the most suitable acceleration- displacement graph will be​

Answer 1

Answer:

(d)

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Answer 2

Answer:

The answer is option A

Explanation:

In this problem, we will use equation of straight-line graph (linear equation) y=mx+c

In this equation, m is the slope of the graph and c is the interception on y− axis

Now according to the problem initial velocity =v0​

Let the distance travelled in time i=x0​.

For the graph tanθ=x0​v0​​=xv0​−v​.....(i)

where v is velocity and x is displacement at any instant of time t

From eq (i) v0​−v=x0​v0​​x

⇒v=x0​−v0​​x+v0​

We know that

b) Acceleration a=dtdv​=x0​−v0​​dtdx​+0

⇒a=x0​−v0​​(v)

=x0​−v0​​(x0​−v0​​x+v0​)=x02​v02​​x−x0​v02​​