Question

The velocity function of an object moving along a straight line is given by v(t)=At^2+Bt. If at t=2s,the velocity is 3m/s and acceleration is 0.500m/s^2,find the value of the constant A.

Answer 1

Answer:

-0.25 ,2

Explanation:

4A+2B=3

6A+B=0.5

Or 12A+2B=1

By solving

A= -0.25 ,B=2