Question

The velocity (in ms ) of an object changes from
V = {i + j) to V2 = (2i – 2]) in 2 s. The magnitude of
average acceleration is
2 ms-2
5 ms-2
10
TO
ms
1 ms-2​

Answer 1

Answer:

1.28 ms-2 os the answer I think

Answer 2

GIVEN : $V_{1}$ = {i+j}

$V_{2}$ = {2i-2j}

t=2sec

TO FIND :

Average acceleration ?

solution:

By using formula , average acceleration = $\frac{V_{2}-V_{1} }{t}$ = 2i-2j-i+j/2

= {i-3j}/2

=$\sqrt{1+9}$/2 = $\sqrt{10}$/2= 1.58 m/$s^{2}$