Question

The velocity of 800gm object changes from 3i^-4j^ to 6i^+2k^. The change in kinetic energy is

Answer 1

change in kinetic energy=mass÷(change in velocity)^2

change in velocity,

∆v=3i+4j+2k

|∆v|=

$\sqrt{ {3 }^{2} + {4 }^{2} + {2}^{2} }$

=√29

∆K.E.=

$\frac{1}{2} \times.8 \times 29$

$11.6joule$