Question

the velocity of a and b are a=i+j m/s and b=3i-2j m/s the velocity of b as seen by a is​

Answer 1

Answer:

Let us consider the values as following:

r1=(3i+5j)mr2=(−5i+3j)mv1=(4i−4j)m/sandletv2be=(−ai−3j)m/st=2sec

If two particles collides after time "t" they travel equal distance.

r1+v1t=r2+v2t(3i+5j)+(4i−4j)×2=−5i+3j+(−ai−3j)2onsolvingweget,3i+8i+5j−8j=−5i+3j−2ai−6i11i+5i−3j=−2ai−3j16i=−2aia=2−16=−8m/s2

Answer 2

Explanation:

Thanks for A2A

Refer to the above image for the solution