The velocity of a ball of mass 100 grams
At an instant is (5^i+6^j)cm/s then its K.E in ergs will be
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Answered by
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Velocity vector (v->) = 5 i + 6 j cm/s
So,
|v| = √5^2 + 6^2 = √ 25+36 = √ 61 cm/s
Now,
Kinetic Energy = 1/2*m*v^2 = 1/2*100*√61^2 = 100*30.5 = 3050 ergs
Hope this helps you !
So,
|v| = √5^2 + 6^2 = √ 25+36 = √ 61 cm/s
Now,
Kinetic Energy = 1/2*m*v^2 = 1/2*100*√61^2 = 100*30.5 = 3050 ergs
Hope this helps you !
Answered by
0
Kinetic energy=1/2mv²
m=100/1000kg=1/10kg
v=5^i+6^j
→K=1/20(5^i+6^j)²
→K=1/20(25+36)
→K=61/20J=61/20×10000000ergs=61000000/2=30500000ergs
Hope this will help you!!!!!
m=100/1000kg=1/10kg
v=5^i+6^j
→K=1/20(5^i+6^j)²
→K=1/20(25+36)
→K=61/20J=61/20×10000000ergs=61000000/2=30500000ergs
Hope this will help you!!!!!
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