Question

) The velocity of a body changes from 40 m/s to 90 m/s in 10 s find the acceleration of

the body?​

Answer 1

Answer:

Explanation: v=u+at

It is given that v= 90 m/s,u=10m/s,t=10s

90=40+a(10)

90-40=10a

50=10a

a=50/10

a= 5m/s^2

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Answer 2

Explanation:

Given

vi 40m/s

vf =90m/s

∆t= 10s

a =∆v/∆t. . . . . . . 1

∆v = vf - vi/ t

so

a = vf- vi /∆t. . . . . . . 2

putting values in equation

a = 90 - 40/10

a= 50/10

a= 5 m/s2

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