Question

) The velocity of a body changes from 40 m/s to 90 m/s in 10 s find the acceleration of

the body?​

Answer 1

Given :-

• Initial velocity = 40 m/s

• Final velocity = 90 m/s

• Time = 10 s

To Find :-

• Acceleration of the body

Solution :-

$\large \implies \boxed{\boxed{\sf \orange{ a = \dfrac{v - u}{t}}}}$

$\large \implies \sf a = \dfrac{90 - 40}{10}$

$\large \implies \sf a = \dfrac{50}{10}$

$\large \implies\boxed{ \sf \purple{ a = 5 \: {ms}^{ - 2}}}$

Acceleration of the body is 5 m/s²

Answer 2

Given :-

• Initial velocity (u) = 40m/s
• Final velocity (v) = 90m/s
• Time (t) = 10s

To Find :-

• Calculate the acceleration of the body.

Solution :-

Applying 1st equation of motion,

v = u + at

=> 90 = 40 + a × 10

=> 90 = 40 + 10a

=> -10a = 40 - 90

=> -10a = -50

=> 10a = 50

=> a = 5m/s²

Therefore, The Acceleration of the body is 5m/s².