Question

The velocity of a body changes from 60 m/s to 30 m/s in 5 seconds , it's Acceleration is

Answer 1

Answer:

Given that, initial velocity (u) of the body is 60 m/s and final velocity (v) of the body is 30 m/s.

Also, given that time (t) is 3 seconds.

We have to find the acceleration (a) of the body.

Using First Equation of Motion,

⇒ v = u + at

Substitute the known values

⇛ 30 = 60 + a(3)

⇛ 30 - 60 = 3a

⇛ -30 = 3a

Divide by 3 on both sides

⇛ -30/3 = 3a/3

⇛ -10 = a

⇛ a = -10 m/s²

(Negative sign shows retardation pr deceleration)

\rule{200}2

Additional Information

Acceleration is defined as a change in an object's velocity over time.

i.e. a = ∆v/t or a = (v - u)/t

It's S.I. unit is m/s².

Answer 2

Answer:

Hi

This is your answer..

Acceleration = final velocity- initial velocity/ time

So the final velocity is 22 and the initial is 10 and the time is 6.5

So acceleration= 22meters -10meters/6.5seconds

12/6.5= 1.84m/s^2

Acceleration is 1.84 m/s^2