The velocity of a body changes from 65 m/s - 98 m/s by Time of 12 s . What is distance covered by body if acceleration is 2.75 m/s2.
Answers
Answer:
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Step-by-step explanation:
➡️ Answer: Distance covered by body if acceleration is 2.75 m/s² is 978 m ..
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Answer:
Step-by-step explanation:
Question:
The velocity of a body changes from 65 m/s - 98 m/s by time of 12 s. What is distance covered by body if acceleration is 2.75 m/s².
Answer:
Distance covered by body if acceleration is 2.75 m/s² is 978 m.
Explanation:
Given that:
Initial velocity (u) = 65 m/s
Final velocity (v) = 98 m/s
Time taken (t) = 12 s
Acceleration (a) = 2.75 m/s²
To Find:
Distance covered (s)?
Solution:
Using second equation of motion ::
We know that,
Where,
s denotes distance covered
u denotes initial velocity
t denotes time taken
a denotes acceleration
According to the question by using the formula we get,
∴ Hence, distance covered by body if acceleration is 2.75 m/s² is 978 m.
Additional Information:
clubsuit♣ Three equations of motion ::\
\
v = u + at
s = ut + ½ at²ㅤㅤ[Used above]
v² = u² + 2as
\clubsuit♣ Some important definitions ::
Acceleration
Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change in velocity is considered as acceleration.
- Initial velocity
Initial velocity is the velocity of the object before the effect of acceleration.
- Final velocity
After the effect of acceleration, velocity of the object changes. The new velocity gained by the object is known as final velocity.