Question

the velocity of a body increases at a constant rate from 20 ms^-1 to 50 ms^-1 find the acceleration​

Answer 1

Answer

Acceleration = 2 m/s²

⊕ Given [ Corrected ]

Velocity of a body increases at a constant rate from 20 m/s to 50 m/s in 10 s

⊕ To Find

Acceleration

⊕ Key Points

We know that , " Acceleration is defined as rate of change in velocity "

$\orange{\bigstar}\ \; \blue{\bf a=\dfrac{v-u}{t}}\ \; \green{\bigstar}$

SI unit of acceleration is m/s²

SI unit of velocity is m/s

SI unit of time is second

⊕ Solution

Initial velocity , u = 20 m/s

Final velocity , v = 50 m/s

Time , t = 10 s

Acceleration , a = ? m/s²

Now , Apply formula for acceleration ,

$\to \rm a=\dfrac{v-u}{t}\\\\\to \rm a=\dfrac{50-20}{10}\\\\\to \rm a=\dfrac{30}{10}\\\\\to \rm a=\dfrac{3}{1}\\\\ \bf \orange{\bigstar}\ \; a=3\ m/s^2\ \; \green{\bigstar}$

So , Acceleration = 3 m/s²

Answer 2

$\orange{\bigstar}$  Answer :  $\green{\bigstar}$  

Initial velocity = 20 m/s

Final velocity = 50 m/s

Time = 10 s   [ Not given in question ]

Acceleration = ? m/s²   [ To Find ]

Apply 1st equation of motion ,

→ v = u + at

where ,

v denotes final velocity

u denotes initial velocity

a denotes constant acceleration

t denotes time

So ,

$\rm :\implies v=u+at\\\\\rm :\implies (50)=(20)+a(10)\\\\\rm :\implies (50)-(20)=10a\\\\\rm :\implies 30=10a\\\\\rm :\implies 10a=30\\\\\rm :\implies a=3\ m/s^2$

So , Acceleration = 3 m/s²

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Acceleration and retardation are same but in opposite direction

SI unit of acceleration is m/s²