Question

The velocity of a body is given by v=3t² find the average velocity from t=2 to t=5.... please do all the steps including integration​

Answer 1

Answer:

Just a simple bit : ANsWer is 49.5m/s

Explanation:

Here there nothing to do integration and differentiation.

If he asked acceleration by giving this data we should differentiate the equation v = 3t².

And if he asked distance by giving this equation we should do integration.

But the actual thing is he asked us the average velocity.

So, At t=2

v° = 3 x 2² = 3 x 4 = 12

At t=5

v = 3 x 5² = 3 x 25 = 75

Now the average velocity = (12 + 75) ÷ 2 = 49.5

Thank you ;