Question

the velocity of a body moving along a straight line varies with the position as V=x^2+2x+7 where x is in mts.if the acceleration of the body at x=2m is 15nm/s^2 ,then find n​

Answer 1

The value of n is equal to 2/5.

Given the relation between velocity and the position of the particle , V = x²+2x+7 .

To get a relation between acceleration and position of the particle , we will differentiate V with respect to x.

acceleration = a = dv/dt

Differentitaing V with respect to x to get the value of acceleration.

acceleration = a = dv/dt

=> a = 2x + 2

=> a = 2×2 + 2 (for x = 2m)

=> a = 6 m/s²

a = 6 = 15n

=> n = 2/5

The value of n is equal to 2/5.

Answer 2

Answer:

n= 6

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