The velocity of a body moving at an initial speed of 20 m/s and having an acceleration of
4 m/s after 2 s will be
Answers
Answered by
19
Answer:
Initial speed, u=20m/s
Final speed, v =?
Acceleration, a = 4m/s2
And, Time, t = 2s
Now, v = u + at
So, V = 20 + 4 x 2V = 20 + 8
V = 28m/s
Thus, after two seconds, the speed will be 28m/s.
Answered by
40
Answer:
Initial speed of the body = 20 m/s.
Acceleration = 4 m/s.
Time = 2 s.
Using the first equation of motion :
⇒ v = u + at
⇒ v = 20 + 4*2
⇒ v = 20 + 8
⇒ v = 28 m/s
Hence, the velocity of the body after 2 s will be 28 m/s.
Important Formulas :
- v = u + at
- v² - u² = 2as
- s = ut + ½at²
- a = dv/dt
- v = ds/dt
- a = (dv/ds)v
- ∆x = x2 - x1
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