Question

the velocity of a body moving at an initial velocity of 20m/s and having an acceleration of 4m/s2 after 2s will ​

Answer 1

Answer:

28 m/s2

Explanation:

a=v-u/s

a×s=v-u

(a×s)+u=v

8+20=v

v=28m/s2

Answer 2

Answer:

• Final velocity is 28 m/s.

Given:

• Initial velocity = 20 m/s
• Acceleration = 4 m/s²
• Time taken = 2 sec

Explanation:

$\rule{300}{1.5}$

Here, we are given that a body moving with initial velocity of 20 m/s accelerates at the rate of 4 m/s². We are asked to find it's final velocity after 2 sec.

From first kinematic equation we know,

$\longrightarrow{\sf{v\ =\ u\ +\ at}}$

Here,

• v denotes final velocity
• u denotes initial velocity
• a denotes acceleration
• t denotes time taken

Solving,

$\longrightarrow{\sf{v\ =\ u\ +\ at}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 20\ +\ 4 \times 2}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 20\ +\ 8}} \\ \\ \\ \longrightarrow{\sf{v\ =\ 28\ m/s}}$

∴ The final velocity of the body is 28 m/s.

$\rule{300}{1.5}$