The velocity of a body of mass 10 kg increases from 4 m per second to 8 m per second when a force acts on it for 2 seconds. what is the gain in momentum per second?
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hey buddy here is your answer by UDIT
Method 1:
initial momentum=mu = 10 × 4 =40
final momentum=mv= 10 × 8 =80
momentum gain in per second
=(80-40)/2
=20kgm/s^2 =20 N
Method 2 :
gain of momentum per second is also known as Force
Force = m a
m=10 kg
a= ( v-u)/t
a=(8-4)2
a= 2 m/ s^2
Force = 10× 2 = 20 N
Method 1:
initial momentum=mu = 10 × 4 =40
final momentum=mv= 10 × 8 =80
momentum gain in per second
=(80-40)/2
=20kgm/s^2 =20 N
Method 2 :
gain of momentum per second is also known as Force
Force = m a
m=10 kg
a= ( v-u)/t
a=(8-4)2
a= 2 m/ s^2
Force = 10× 2 = 20 N
inshasaleen:
thnk uuuh soo much
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