The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when al
on it for 2
(a) What is the momentum before the force acts ?
(b) What is the momentum after the force acts 7
(c) What is the gain in momentum per second ?
(d) What is the value of the force
Answers
( a ) Momentum before the force acts :
( b ) Momentum after the force acts :
( c ) Gain in momentum per second :
( d ) The value of the force :
_________________________________________
➛Mass of the body = 10 kg.
➛Initial velocity u = 4 m/s.
➛Final velocity v = 8 m/s.
➛Time t = 2s.
_________________________________________
( a ) Momentum before the force acts :
( b ) Momentum after the force acts :
( c ) Gain in momentum per second :
( d ) The value of the force :
_________________________________________
We are given,
➛Mass of the body ( m ) = 10 kg.
➛Initial velocity ( u ) = 4 m/s.
➛Final velocity ( v ) = 8 m/s.
➛Time t = 2s.
Now, Let's solve each Question one by one.
( a ) Momentum before the force acts :
We know ,
= 10 x 4 = 40 kg.m/s
Momentum before the force acts : 40 kg.m/s
( b ) Momentum after the force acts :
= 10 × 8 = 80 kg.m/s
Momentum after the force acts : 80 kg.m/s.
( c ) Gain in momentum per second :
= 80 - 40 = 40 kg.m/s
Gain in momentum per second : 40 / 2
Gain in momentum per second : 20 kg.m/s.
( d ) The value of the force :
acceleration : 2 m/s²
Force = 10 × 2
Force = 20 N.
The value of the force : 20 N.