Question

The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s. a) What is the momentum before the force acts? b) What is the momentum after the force acts? c) What is the momentum gain per second? d) What is the value of the force? Please can someone help me.....

Answer 1

Answer & Explanation:

Given,

Mass (m) = 10kg

Initial Velocity (u) = 4 m/s

Final Velocity (v) = 8 m/s

Time (t) = 2s

i. Momentum = Mass*Initial Velocity

= 10*4 kg.m/s

= 40 kg.m/s

ii. Momentum = Mass*Final Velocity

= 10*8 kg.m/s

= 80 kg.m/s

iii. Rate of Change of Momentum = (mv-mu)/t

= (80-40)/2 kg.m/s

= 20 kg.m/s

iv. Force = Mass*Acceleration

= 10*2 N

= 20 N

Hope this helps.