The velocity of a body of mass 10 kg increases from 4 m/s to 8 m/s when a force acts on it for 5 s. Find (a) the momentum before the action of force (b) the momentum after the action of force (c) the magnitude of force.
Answers
Answer:
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Step-by-step explanation:
Initial velocity (u) = 4 m/s
Final velocity (v) = 8 m/s
Mass (m) = 10 kg
Time (t) = 2 seconds
Initial momentum (p₁) = m × u
Final momentum (p₂) = m × v
(a)
Momentum before the force act = Initial momentum
= m × u
= 10 × 4
= 40 kg.m/s
(b)
Momentum after the force act = Final momentum
= m × v
= 10 × 8
= 80 kg.m/s
(c)
Momentum gain = Final momentum - Initial momentum
= 80 - 40 = 40 kg.m/s
Momentum gain in momentum per second = Momentum gain / time
= 40 / 2 = 20 kg.m/s
(d)
Force = mass × acceleration
= m × (v - u) / t ( as, acceleration is change in velocity per time)
= 10 × (8 - 4) / 2
= 10 × 2
= 20 N
Answer:
BLA BLA BLA MF
Step-by-step explanation: