Question

the velocity of a body of mass 10 kg increases from 4m/s to 8m/s when a force acts on it for 2 seconds ​

Answer 1

Answer:

10 kg - 4 =6

8 -6=2

Explanation:

I think so

Answer 2

Answer:

Force :

It is defined as mass times the acceleration .

$\bigstar\ \; \sf \huge{\red{F=ma}}$

Acceleration :

It is defined as rate of change in velocity .

$\bigstar\ \; \sf \huge{\green{a=\dfrac{v-u}{t}}}$

So ,

$:\implies \sf F=ma: \\ :\implies \sf F=\dfrac{m(v-u)}{t}:$

Given ,

• Mass , m = 10 kg

• Initial velocity , u = 2 m/s

• Final velocity , v = 8 m/s

• Time , t = 4 s

$:\implies \sf F=\dfrac{10(8-2)}{4}:$

$</p><p>:\implies \sf F=\dfrac{10(6)}{4}:$

$:\implies \sf F=\dfrac{60}{4}: \\ </p><p> </p><p></p><p>:\implies \sf \blue{F=15\ N}\ \; \bigstar:</p><p>$

So , Magnitude of the force applied is 15 N