Question

the velocity of a body of mass 10 kg increases from 4m/s to 8m/s when a force acts on it for 2 s.what is the value of the force??

Answer 1

Answer:

Here is your answer....

Explanation:

Mass of the body =10 kg

Initial velocity u=4 m/s

Final velocity v=8 m/s

Time t= 2s

a) Momentum before force acts p1 = m X u = 10 X 4 = 40 kg.m/s

b) Momentum after force acts p2 = m X v = 10 X 8 = 80 kg.m/s

c) Gain in momentum per second = 40/2 = 20 kg.m/s

d) Acceleration a = v-u / t = 8-4/2 = 2m / s^2

Force = m X a = 10 X 2 = 20 N