Question

The velocity of a body of mass 10kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s

a) what is the momentum before the force acts?
b) what is the momentum after the force acts?

Answer 1

a) momentum of a body before the force acts = mass × initial velocity => 10×4 => 40 kg.m/s

b) momentum of a body after the force acts = mass × final velocity => 10×8 => 80 kg.m/s
hope this helps

Answer 2

QUESTION ---- The velocity of a body of mass 10kg increases from 4 m/s to 8 m/s when a force acts on it for 2 s

ANSWER
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FORMULAS
Momentum = Mass × Velocity

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Mass = 10 kg
Initial velocity = 4 m/sec

Initial Momentum = Mass × Initial velocity

Initial Momentum = 10 × 4

Initial Momentum = 40 kg m/sec

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Mass = 10 kg
Final Velocity = 8 m/sec

Final Momentum = Mass × Final Velocity

Final Momentum = 10 × 8

Final Momentum = 80 kg m/sec
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Change in Momentum = Final Momentum - Initial Momentum

Change in Momentum = 80 - 40

Change in Momentum = 40 kg m/sec

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According to Newton's Second Law,

Change in Momentum ( ∆p ) = 40 kg m/sec
Time = 2 Seconds

Force = ∆p / t

Force = 40 / 2

Force = 20 N

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HOPE IT HELPS :):):)::):)