Question

The velocity of a body of mass 10kg increases from 4 m/s to 8m/s when force acts on it for two seconds
Find A) what is the momentum of the body before the force acts.
B) what is the gain in momentum per second
C) what is the value of the force

Answer 1

a) m=10kg t=2s
u=4m/s
v=8m/s
then momentum before force acts is p=mu=10×4=40kg m/s
c)a=v-u/t=8-4/2=2m/s^2
then f=ma=10×2=20N