The velocity of a body of mass 2 kg as a function of time (t) is given by v = 2titt jms 1. The force acting on the body at t = 2 s is : (1) 41 + 8jN (2) 81 + 4 jN (3) 21 + 4jN (4) 41 + 2jN........reply FAST
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Answer:
Here, m=2kg
υ(t)=2t
ˆ
i
+22
ˆ
j
t=2s
→
υ
=4
ˆ
i
+4
ˆ
j
=4(
ˆ
i
+
ˆ
j
)
∴
→
p
=
→
mυ
=2(4
ˆ
i
+4
ˆ
j
)=[8
ˆ
i
+8
ˆ
j
]kgms-1
Also,
→
a
=
d
→
v
dt
=
d
dt
[at
ˆ
i
+t2
ˆ
j
]
→
a
=2
ˆ
i
+2t
ˆ
j
At t=2s,
→
a
2
ˆ
i
+4
ˆ
i
→
F
=m
→
a
=2(2
ˆ
i
+4
ˆ
j
)=(4
ˆ
i
+8
ˆ
i
)N.
Explanation:
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