Physics, asked by dny791999, 11 months ago

The velocity of a body of mass 20 kg decreases from 20
m/s to 5 m/s in a distance of 100 m force on the body is​

Answers

Answered by akshaygandhirock
3

vv^{2} = u^{2} +2as

25-400/200=a

a=-375/200

f=ma

F= 20x-375/200

F=-37.5N

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