Question

The velocity of a body of mass 20kg decrease from 20ms-' to 5mg-' in a distance of 100m . Force on the body is

Answer 1

Answer:

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Explanation:

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Answer 2

Answer:

Heya user !!!

Here's the answer you are looking for

Initial velocity (u) = 20m/s

Final velocity (v) = 5m/s

Distance travelled (s) = 100m

Using the 3rd equation of motion,

v² - u² = 2as where a is the acceleration

5² - 20² = 2a (100)

25 - 400 = 200a

- 375 = 200a

a = - 375 / 200 = - 1.875

So, the acceleration is - 1.875 m/s²

Now,

Force = mass × acceleration

= 20 kg × (- 1.875) m / s²

= -37.5 kgm/s²

= -37.5 N

(negative sign indicates that the force is opposite to the direction of motion.)

Therefore, the force on the body is - 37.5 N

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