Question

The velocity of a body of mass 20kg decreases from 20m/s to 5m /s in a distance of force on the body is

Answer 1

$hey \: mate \: heres \: ur \: answer \:$
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$Question:$

$The \: veocity \: of \: a \: body \: of \: \: \: mass \\ \: 20kg \: decreases \\ from20m/s \: to \: 5m/s \\in \: a \: distance \: of \: 100m.\\ Force \: of \: the \: body \: is:$
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$Answer \: \\ \\ F(force) = - 37.5$
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Step by step explaination:

$The \: equation \: of \: motion \: is \: \\ given \: as$

${v}^{2} = {u}^{2} + 2as$

$( {5})^{2} = ({20})^{2} + 2 \times a \times 100$

$25 = 400 + 200a$

$25 - 400 = 200a$

$- 375 = 200a$

$a = \frac{ - 375}{200}$

$a = - 1.875m/{s}^{2} \:$
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$The \: force \: is \: given \: as \:$

$F = ma \:$

$F= 20 \times ( - 1.875)$

$af= - 37.5N$

$thus \: the \: force \: on \: the \: body \: is \: - 37.5N$
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HOPE THIS HELPS YOU!!! ^_^