Physics, asked by thebustle01, 13 hours ago

The velocity of a body of mass 5 kg acted upon by a constant retarding force of 10 N reduces to half of its initial value in 2 seconds, then initial velocity of the body is 3 m/s o 8 m/s 12 m/s 14.5 m/s​

Answers

Answered by rsagnik437
153

Answer :-

Initial velocity of the body is 8 m/s .

Explanation :-

We have :-

→ Mass of the body (m) = 5 kg

→ Force acting (F) = 10 N

→ Time taken (t) = 2 sec

________________________________

Let the initial velocity of the body be u m/s . Then final velocity of the body will be u/2 m/s as it reduces to half of it's initial value .

Also as the force acting is a retarding force, so it's value will be -10 N .

________________________________

Finally, putting values in Newton's 2nd law of motion, we get :-

F = m(v - u)/t

⇒ -10 = 5(u/2 - u)/2

⇒ -10(2) = 5u/2 - 5u

⇒ -20 = (5u - 10u)/2

⇒ -20(2) = -5u

⇒ -40 = -5u

⇒ u = -40/-5

u = 8 m/s


Ladylaurel: Great! :)
Asterinn: Nice! ( ╹▽╹ )
rsagnik437: Thank you :)
Answered by MяMαgıcıαη
117

Answer:

  • Initial velocity (u) = 8 m/s

Explanation:

Given information,

The velocity of a body of mass 5 kg acted upon by a constant retarding force of 10 N reduces to half of its initial value in 2 seconds, then initial velocity of the body is?

  • Mass (m) = 5 kg
  • Force (F) = 10 N
  • Time taken (t) = 2 seconds
  • Initial velocity (u) = ?

Now, let's find acceleration (a) by using first equation of motion. We clearly know that it is given by;

  • v = u + at

➻ v - u = at

➻ (v - u)/t = a

a = (v - u)/t

  • Hence, acceleration is (v - u)/t m/.

Now, let's find its initial velocity (u) by using Newton's second law of motion. We clearly know that it is given by;

  • F = ma

Here, given force is retarding so its value will be in negative and we know that the velocity of a body to half of its initial value i.e, v = half of u. Therefore;

  • Force (F) = -10 N
  • Final velocity (v) = u/2 m/s

Putting all values,

➻ -10 = 5[(v - u)/t]

➻ -10 = 5 × (u/2 - u)/2

➻ -10 = 5 × (u/2 - 2u/2)/2

➻ -10 = 5 × [(u - 2u)/2]/2

➻ -10 = 5 × (-u/2)/2

➻ -10 = 5 × -u/2 ÷ 2

➻ -10 = 5 × -u/2 × 1/2

➻ -10 = 5 × (-u × 1)/(2 × 2)

➻ -10 = 5 × -u/4

➻ -10 ÷ 5 = -u/4

➻ -10/5 = -u/4

➻ -2 = -u/4

➻ -2 × 4 = -u

➻ -8 = -u

➻ 8 = u

u = 8

  • Hence, initial velocity is 8 m/s.

Important definitions,

  • Mass

Weight or quantity of matter in any object is known as mass.

  • Force

A push or pull applied on an object is known as force.

  • Acceleration

Acceleration is the process where velocity changes. Since, velocity is the speed and it has some direction. So, change in velocity is considered as acceleration.

  • Initial velocity

Initial velocity is the velocity of the object before the effect of acceleration.

  • Final velocity

After the effect of acceleration, velocity of the object changes. The new velocity gained by the object is known as final velocity.

▬▬▬▬▬▬▬▬▬▬▬▬

Similar questions