Question

The velocity of a body of mass m revolving in a vertical circle of radius r at the lowest point 2✓2gr

Answer 1

wht I hv to find bro

Answer 2

Answer:

Concept:
Application of Newton's Laws of Motion

Explanation:

Given:

The velocity of a body of mass m

Revolving in a vertical circle of radius r

At the lowest point 2✓2gr
Find:

The minimum tension in the spring

Solution:

Refer to the image for the assumed vertical circle

                                 $\begin{aligned}&\begin{aligned}&T^{\prime}+mg=\frac{m v^{2}}{R} \\&T^{\prime}=\frac{m v^{2}}{R}-mg \\&T-m y=\frac{m u^{2}}{R} \\&T=\frac{m v^{2}}{R}+mg\end{aligned}\end{aligned}$

       Given,    $u &=2 \sqrt{2 g R} \\&=\sqrt{8 g R}$

                     $work \ done \ by \ all &=k f-k i \\ \\ -m g(2 R) &=\frac{1}{2} m v^{2}-\frac{1}{2} m(8 g R)$

                               $2 g R &=\frac{1}{2} v^{2} \\\\v^{2} &=4 g R$

By substituting the $v^{2}$ value in the $&T^{\prime}$ equation,

                              $\begin{aligned}&T^{\prime}=\frac{m(4 g R)}{R}m g \\&T^{\prime}=3 m g\end{aligned}$

So, the tension will be 3mg

#SPJ3