Question

the velocity of a body of mass10 kg increase from 4m/s to 8m/s when a force acts on it for 2sec what is the value o f Force
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Answer 1

Answer:

given,

mass (m) = 10 kg

intial velocity (u) = 4m/s

final velocity (v) = 8m/a

time (t) = 2 sec

now put the given values as per the formula...

Explanation:

we know ,

v = u + at

=> 8 = 4 + a x 2

=> 8 - 4 = 2a

=> 4/2 =a

2 = a

hence we got acceleration ( a ) = 2 m/s²

we know the formula for force i.e.,

F = m x a

F = 10 x 2

F = 20N

here is your answer

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Answer 2

Answer:

u(initial velocity) = 4m/s

v(final velocity) = 8m/s

t(time) = 2 s

m(mass) = 10kg.

acceleration = (v-u)/t

by putting values

(8-4)/2

= 4/2 = 2m/s^2

Force = mass × acceleration

= 10×2

= 20N (answer)