Physics, asked by gauthamsankars8, 1 month ago

The velocity of a body starting from rest is20m/s in the 4th second and 40m/s in the 8th second. What is the distance traveled by the body between 4th and 8th second?​

Answers

Answered by sanchitapramanik533
3

Explanation:

Velocity at the 4

th

second u=20m/s

Velocity at the 8

th

second v=40m/s

Acceleration a=

t

v−u

=

4

40−20

=

4

20

=5m/s

2

Distance travelled s=ut+1/2at

2

=20×4+1/2×5×4

2

=80+40

=120m

Answered by varshith11111
1

The velocity of a body starting from rest is20m/s in the 4th second and 40m/s in the 8th second. What is the distance traveled by the body between 4th and 8th second?

Explanation:

The velocity of a body starting from rest is20m/s in the 4th second and 40m/s in the 8th second. What is the distance traveled by the body between 4th and 8th second?

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