Question

The velocity of a bullet is reduced from 200 m/s to 100 m/s while travelling through a wooden block of thickness 10 cm the retardation assuming it to be uniform will be

Answer 1

By using 2as=v^2 -u^2we haveu=200m/s v=100m/s& s=0.1m(10cm) from here deacc ( retardation)comes 150000m/s
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Answer 2

Answer:

The retardation is $15\times10^{4}\ m/s^2$.

Explanation:

Given that,

Initial velocity u= 200 m

Final velocity v = 100 m

Distance = 10 cm = 0.1 m

We need to calculate the retardation

Using equation of motion

$v^2=u^2-2as$

$200^2=100^2+2\times a\times10\times10^{-2]$

$a = \dfrac{(200)^2-(100)^2}{2\times10\times10^{-2}}$

$a =-150000\ m/s^2$

Negative sign shows the retardation.

Hence, The retardation is $15\times10^{4}\ m/s^2$.