Question

The velocity of a bullet is reduced from 400 ms-1
to 100 ms-while travelling through material of
thickness of 1 m. The retardation will be​

Answer 1

Answer:

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Answer 2

Given:

• Initial velocity = 400 m/s.
• Final velocity = 100 m/s.
• Thickness is 1 m

To find:

• Retardation will be ?

Calculation:

Let the acceleration of the bullet while passing through the material be "a" m/s².

Now, applying EQUATIONS OF KINEMATICS:

${v}^{2} = {u}^{2} + 2ad$

$\implies \: {100}^{2} = {400}^{2} + 2a(1)$

$\implies \: 10000 = 160000 + 2a$

$\implies \: 2a= - 150000$

$\implies \: a= - 75000 \: m {s}^{ - 2}$

Now, when we want to represent this as retardation, we need to remove the negative sign.

So, retardation of bullet is 75000 m/s².