Question

The velocity of a bullet moving with initial velocity 300 m/second becomes 400 m/sec. Find the distance covered
by the bullet during this period.​

Answer 1

Answer:

Explanation:

Given,

Initial Velocity(u) = 300 m/s

Final Velocity(v) = 400 m/s

To Find :-

Distance covered(h)

Formula Required :-

$v^2-u^2=2gh$

g = 10 m/s^2

Solution :-

$(400)^2-(300)^2=2\times 10\times h$

$160000 - 90000 = 20\times h$

$70000=20\times h$

$h=\dfrac{70000}{20}$

h = 3500

Distance Covered = 3500 m

Know More :-

1) v = u + at

2) s = ut + 1/2 at²

3) s = vt - 1/2at²

4) a = v - u/t

5) v²-u² = 2as