Question

the velocity of a bullet of mass 50g fired with a gun is 20m/s. The kinetic energy of bullet is ​

Answer 1

Explanation:

By the law of conservation of momentum,

Initial momentum = find momentum

∴P

1

=P

2

∴m

1

v

1

=m

2

v

2

here, m

1

=20gm.v

1

=200ms

−1

,m

2

=20kg=20,000gm

∴v

2

=

m

2

m

1

v

1

=

20,000

20×200

∴

v

2

=0.2

m/s

Answer 2

Given:-

• Mass (m) =50gram (0.05kg)
• Velocity (v) =20m/s

To find:-

• Kinetic energy of bullet

Process:-

Kinetic Energy of an object is given by:

$➜ \frac{1}{2} m {v}^{2} Joule$

Therefore, by putting the values of mass and Velocity, we get:

$→ \frac{1}{2} \times 0.05 \times {(20)}^{2}$

$→ \frac{1}{2} \times \frac{5}{100} \times 20 \times 20$

$→10Joule$

• Hence Kinetic Energy is 10Joule

Hope it helps you ✔️