Question

the velocity of a car at 10:50 am is 60 km/h and at 10:52 am it is 80 km/h asuming constant acceleration in the given period find its value​

Answer 1

Answer:

Explanation:

v = 80km/h

u = 60 km/h

v- u = 20 km/h

= 20*5/18 m/s

= 100÷18 m/s

t = 2 minutes = 2*60 s = 120 sec

according to first law of motion

v = u + at

a = (v-u)/ t

a=100÷18÷120 m/s^2

= 0.0462 m/s^×