Question

the velocity of a car at 10:50am is 60km/h and at 10:52 am it is 80km/h. Assuming constant acceleration in the given period, find it's value.
(Ans:600km/h²)​

Answer 1

Answer:

a=v-u/t

80-60/120

1/6

a=1/6

Step-by-step explanation:

Answer 2

Answer:

${\tt{\ \: {\underline{\underline{\huge{☘ Required \: Answer:}}}}}}$

☆Firstly we changed the fractions in m/s

☆1 km/hour = 5/18

☆Changing km/hour in m/s

☆Intial Velocity (U)

$☆60 \: = 60 \times \frac{5}{18} = \frac{50}{3} \\ ⇒16.67$

☆Final Velocity (v)

$☆80 \:= 80 \times \frac {5}{18} = \frac{400}{18} = \\ ⇒22.22 \:$

☆Time Taken (T)

$☆10:52 - 10:50 = 2 \: minutes$

☆Acceleration ⬇️

$☆ \frac{v - u}{t}$

$☆⇒ \frac{22.22 - 16.67}{2} \\ ⇒ \frac{5.55}{2} = 2.775 \: {m/s}^{2}$