Question

The velocity of a car at 17.46hrs is 60 km/ hr and at 17.48 hrs it is 80 km/ hr.find acceleration assuming constant acceleration for the period​

Answer 1

Given :

Velocity of a car at time 17:46 hrs  = 60 km/hr

Velocity of the car at time 17:48 hrs = 80 km/hr

To Find:

Acceleration assuming it to be constant o the given period of time = ?

Solution :

The time difference for the given period is:

Δt = 2 mins

Or, $\Delta t = \frac{2}{60}hr = \frac{1}{30} hr$

The change in velocity for this time period is :

Δv = (80 - 60 ) km/hr = 20 km/hrs

Since we know that acceleration is defined as the rate of change of velocity per unit time :

So , we have :

$a= \frac{\Delta v}{\Delta t}$

  =$\frac{20 km/hr}{\frac{1}{30}hr}$

 =$20 \times 30 km/hr^2$

= $60 km/hr^2$

So the acceleration of the car for the given interval of time is $60 km/hr^2$