Question

The velocity of a car decreases from 30 m/s 15 m/s, when it travels a distance of 100 m. The distance travelled from this position before it comes to rest is

Answer 1

Answer:

First, you have to work out the acceleration. We know the initial velocity (30 m/s) and the final velocity (15 m/s), and the distance over which the deceleration happened (100 m), so we can work out the acceleration:

⇒v²₁=v²₂+2*a*Δx  

⇒(15)²=(30)²+2*a*(100)  

⇒225 = 900 + (200)a  

⇒−675 = (200)a  

⇒−3.375 = a  

Now that we know the acceleration, we can use the same equation to figure out the displacement when v₂ equals 0 :

⇒(0)² = (30)² + 2(−3.375)Δx  

⇒0 = (900) + (−6.75)Δx  

⇒−900 = (−6.75)Δx  

⇒133.3 = Δx  

So, car travels 133.3 m before coming to rest.

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