Physics, asked by uzma29, 1 year ago

the velocity of a car decreases from 43km/hr to 25km/hr in 10 seconds find its retardation

Answers

Answered by NavaN11

The velocity time and acceleration time is given by
at = v -u
Where a is acceleration
v is final velocity and u is initial velocity
t is the time taken

So,
From the data
u=43 km/hr
u=43/3600 km/sec
v=25 km/hr
v=25/3600 km/sec
a=(-43/3600 + 25/3600)/10
a= -0.0005 km/sec²
a= -0.5 m/sec²

So,
The retardation is 0.5 m/sec²

QGP: Hi Sir/Mam. I'm afraid there's a small mistake in the answer. You mistakenly took 1 hr = 60 seconds while calculating. The actual answer would come by 1 hr = 60*60 seconds.

NavaN11: Yes sir its a mistake , i will correct it right away as soon as any moderator sends me the link

QGP: Well Don't rather call me a "Sir" :) I am younger than you. :)

NavaN11: Whatever its a gesture for respect ...its rude to call by first name..i have made the required changes .d

QGP: Okay Sir/Mam. Anyways, Thanks for correcting :)

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