Question

The velocity of a car increases from 54 km/h to 90km/h in 2seconds.what is the acceleration and distance travelled

Answer 1

1) 5ms^-2
2) 40 m
these are the answers

Answer 2

Explanation:

initial velocity, u = 54km/hr = 54×5/18 = 15m/s

final velocity, v = 90km/hr = 90×5/18 = 25m/s

acceleration, a = v - u/t = [25 - 15/2] = 5m/s

also, distance, S = ut + 1/2at^2

= 15 × 2 + 1/2 × 5 × (2)^2

= 30 + 10 =40m