THE VELOCITY OF A CAR INCREASES FROM 54 KM/PER HOUR TO 72KM/PER HOUR HOW MUCH WORK DONE IF MASS=1500 KG GIVE ANSWERS FIRST TO MARK IT BBRAINLIEST answer fasttt
Answers
Given:-
- Initial velocity (u) = 54×5/18= 15m/s
- Final velocity (v) = 72×5/18= 20m/s
- Mass of car (m) = 1500kg
To Find:-
- Work done (W).
Solution:-
As we know that change of kinetic energy is called work done. so by using the formula of kinetic energy .
→Initial Kinetic Energy = 1/2mu²
Substitute the value we get
→ Initial Kinetic = 1/2×1500×15²
→ Initial Kinetic = 750×225
→ Initial Kinetic = 168750 Joule
And Now Calculating the final kinetic energy
→ Final kinetic = 1/2mv²
Substitute the value we get
→ Final kinetic = 1/2×1500×20²
→ Final kinetic = 750×400
→ Final Kinetic = 300000 Joule
Now, Calculating Work done
Work done = Final Kinetic- Initial Kinetic
→ W = 300000 - 168750
→ W = 131250Joule
∴ The work done is 131250 Joule.
Answer:
131250 Joule
Explanation:
=>Mass of car m = 1500 kg
=> Initial velocity = 54 km/h = 54 x 5/18 = 15 m/s
=> Final velocity = 72 km/h = 72 x 5/18 = 20 m/s
=> Initial kinetic energy = 1/2 mv2
=> K.E = 1/2 x 1500 x (15)2
=> K.E = 168750 J
Increased kinetic energy = 1/2 mv2
=> K.E = 1/2 x 1500 x (20)2
=>K.E = 300000 J
Work done = Change in kinetic energy
=> w = 300000 - 168750
=> w = 131250 J
Hence the work done by the force on the car = 131250J