The velocity of a car increases from 54km/hr to 72 km/hr. How much is the work done if the mass of the car is 1500kg
Answers
Answered by
358
Mass of car m = 1500 kg
Initial velocity = 54 km/h = 54 x 5/18 = 15 m/s
Final velocity = 72 km/h = 72 x 5/18 = 20 m/s
(1 km/h = 1000 m/ (3600 s) = 5/18 m/s
Initial kinetic energy = ½ mv2
= ½ x 1500 x (15)2
= 168750 J
Increased kinetic energy = 1/2 mv2
= ½ x 1500 x (20)2
= 300000 J
Work done = Change in kinetic energy
= 300000 - 168750
= 131250 J
Hence the work done by the force on the car = 131250J
Initial velocity = 54 km/h = 54 x 5/18 = 15 m/s
Final velocity = 72 km/h = 72 x 5/18 = 20 m/s
(1 km/h = 1000 m/ (3600 s) = 5/18 m/s
Initial kinetic energy = ½ mv2
= ½ x 1500 x (15)2
= 168750 J
Increased kinetic energy = 1/2 mv2
= ½ x 1500 x (20)2
= 300000 J
Work done = Change in kinetic energy
= 300000 - 168750
= 131250 J
Hence the work done by the force on the car = 131250J
Answered by
26
Answer:
131250J
Explanation:
initial kinetic energy =54km/hr*5/18m=15m/s
final kinetic energy=72km/hr *5/18=20m/s
kinetic energy =1/2mv2
=1/2*1500*(15)2
=168750J
final kinetic energy
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